Mathematic who can help me for solve it? a^-1.b^-1.c^-1=2 =&gt; (abc)^4=? i nede your help bro&sis

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Mathematic who can help me for solve it? a^-1.b^-1.c^-1=2 => (abc)^4=? i nede your help bro&sis

Corrections · 11

Mathematics

Who can help me solve these equations?
a^-1*b^-1*c^-1=2

(abc)^4=?

I need your help, brothers and sisters.

Thanks Mohammad... also your name great ^_^ see you again...

(x^2-5x)/(x^2-1).(x^2-4x+3/(x^2-8x+15)=(x.(x-5)/(x-1).(x+1)).((x-1).(x-3)/(x-5).(x-3))=x/x+1

i want ask one more question too and it's last :) promise. (x^2-5x)/(x^2-1).(x^2-4x+3/(x^2-8x+15) make it simplify :) thanks...

May I bring my medical problems to italki too?

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